Treatment of neonatal hypophosphataemia: answers

Abstract
QUESTION 1
What daily dose, in mmol, of phosphate is required to treat this child?
- 1.2 mmol/kg/day × 1.2 kg = 1.44 mmol/day
QUESTION 2
What volume, in ml, of 21.6% sodium glycerophosphate will be needed to provide the daily dose calculated in Question 1?
- From the chemical formula it can be seen that each molecule of sodium glycerophosphate contains one atom of phosphate. Therefore, 1 mole of sodium glycerophosphate molecules will contain 1 mole of phosphate atoms
- The stock solution is 21.6% w/v so 100 ml of the stock will contain 21.6 g of sodium glycerophosphate
- 21.6 g of glycerophosphate/molecular mass of 216 g/mol = 0.1 moles/100 ml = 100 mmol/100 ml = 1 mmol/ml
- To give 1.44 mmol/day they need to be infused with 1.44 mmol/1 mmol/ml = 1.44 ml/day
- This would require an hourly infusion rate of (1.44 ml/day/24 hours/day) = 0.06 ml/hour of stock solution
What daily dose, in mmol, of phosphate is required to treat this child?
What volume, in ml, of 21.6% sodium glycerophosphate will be needed to provide the daily dose calculated in Question 1?
The infusion rate for undiluted solution will be too low to administer through a rate controlled pump, so if you dilute 10 ml of 21.6% solution to 50 ml what infusion rate should the pump be set at, in ml/hour?
Using sodium glycerophosphate in this way can provide a significant amount of sodium, what daily dose of sodium, in mmol/kg/day, will this dose of phosphate provide, if administered as sodium glycerophosphate?
To treat this patient, calculate what volume of 13.6% w/v potassium acid phosphate could be used instead of sodium glycerophosphate, to provide an equivalent dose of phosphate with a lower sodium load.
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